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r^2=284
We move all terms to the left:
r^2-(284)=0
a = 1; b = 0; c = -284;
Δ = b2-4ac
Δ = 02-4·1·(-284)
Δ = 1136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1136}=\sqrt{16*71}=\sqrt{16}*\sqrt{71}=4\sqrt{71}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{71}}{2*1}=\frac{0-4\sqrt{71}}{2} =-\frac{4\sqrt{71}}{2} =-2\sqrt{71} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{71}}{2*1}=\frac{0+4\sqrt{71}}{2} =\frac{4\sqrt{71}}{2} =2\sqrt{71} $
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